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直角三角形の数学
 
著者:Mathcot

初版:2007.07.08

Update:2008.01.27



ピタゴラス数
整数a,b,cについてa2+b2=c2が成立するとき(a,b,c)をピタゴラス数という
a,b,cを△ABCの辺とすると△ABCは直角三角形(∠C=90°)
(1) 2n+1:2n(n+1):2n(n+1)+1, (n≧1)
(2)
m2 - n2| : 2mn: m2 + n2 ,m,nは互いに素でどちらかが偶数
(3)
2n:(n2-1):(n2+1)
 
原始ピタゴラス数 













3:4:5
=6:8:10
=9:12:15
=12:16:20
=15:20:25
=18:24:30
=21:28:35
=24:32:40
=27:36:45
=30:40:50
=33:44:55
=36:48:60
=39:52:65
=42:56:70
=45:60:75
=48:64:80
=51:68:85
=54:72:90
=57:76:95
=60:80:100
=63:84:105
=66:88:110
=69:52:65
=72:
=75:
=78:






5:12:13 =10:24:26
=15:36:39
=20:48:52
=25:60:65
=30:72:78
=35:
=40:96:104
=45:
=50:120:130
=55:
=60:
=65:
=70:
=75:






7:24:25
=14:48:50 =21:72:75
=28:96:100
=35:

=42:
=49:
=56:
=63:
=70:
=77:






8:15:17 =16:30:34 =24:45:51 =32:60:68 =40:75:85
=48:
=56:
=64:
=72:135:153






9:40:41 =18:80:82 =27:120:123 =36:160:164 =45:200:205
=54:240:246
=63:
=72:320:328







11:60:61 =22:120:122 =33:180:183
=44:240:244
=55:300:305









12:35:37 =24:70:74 =36:105:111 =48:140:148

=60:








13:84:85 =26:168:170 =39:252:255

=52:336:340
=65:420:425
=78:504:510







15:112:113
=30:224:226 =45:336:339

=60:448:452
=75:560:565







16:63:65
=32:126:130 =48:189:195

=64:252:260









20:21:29
=40:42:58
=60:63:87









28:45:53

=56:90:106










33:56:65

=66:112:130









36:77:85


=72:154:170








39:80:89













40:198:202












48:55:73













57:176:185













65:72:97






 
参考URL
[1]http://club.pep.ne.jp/~asuzui/page9h.html#h1

内接円・外接円
直角剏`を挟む二辺a,bの内接円半径r
r={a+b-√(a2+b2)}/2
直角剏`を挟む二辺a,bの外接円半径R R={√(a2+b2)}/2




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