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f(x,y)=0 |
y'=-fx/fy |
y=f(x) ln y =ln f(x) |
y'= y *
f'(x)/f(x) |
[K1] y=(x2+1)/{ (x-1)(x+2)2} |
[๐] ln y = ln |x2+1|-ln
|x-1|-2ln |x+2| y'/y = 2x/(x2+1)-1/(x-1)-2/(x+2) =-x (x2-2x+7)/{ (x2+1) (x-1) (x+2)} y'=-x (x2-2x+7)/{ (x-1)2(x+2)3} |
[K2] |
[๐] |
diff(f(x),x); |
diff(f(x),x,n); nอnK๗ชฬK |
f(x)
|
f'(x),f(n)(x) |
1/(1-x) dn/dxn 1/(1-x) |
1/(1-x)^2 (d/dx)^n [1/(1-x)]={(2n-1)!/(n-1)!}{1/(1-x)(-2n)} |
ln(x)=loge(x)
ึW |
ln(x)=loge(x) ึWฬ๗ช |
ln(|x|),
ln(x) ln (|f(x)|), ln(f(x)) ln(|x+1|), ln(x+1) ln(|ln(|x|)|), ln(ln(x)) 1/{x ln(|x|)} ,1/(xln(x)) ln{|sin(x)|}, in(sin(x)) |
1/x f'(x)/f(x) 1/(x+1) 1/{x ln(|x|)}, 1/(xlog(x)) -{1+ln(|x|)}/{x ln(|x|)}2, -(1+ln(x)) 1/tan(x) |
ln{|cos(x)|}, ln(cos(x)) |
-tan(x) |
tan(x)
cot(x) sin(ึx) cos(ึx) |
1/cos2(x)=sec2(x)=2/{1+cos(2x)}=1+tan2(x) -1/(sin2(x))=-csc2(x)=-2/{1-cos(2x)}=-1-cot2(x) ึcos(ึx) -ึsin(ึx) |
Update:2007.07.07
Update:2008.02.24/25
Update:2014.03.16